Only care about the first line of libtool --version as otherwise this script

get fooled by libtool 2, and at least libtool 1.5.2x do output the interesting
version string in the first line.
This commit is contained in:
Daniel Stenberg 2009-01-08 22:53:37 +00:00
Родитель 2ed23cb50d
Коммит 0090099565
1 изменённых файлов: 2 добавлений и 2 удалений

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@ -6,7 +6,7 @@
# | (__| |_| | _ <| |___
# \___|\___/|_| \_\_____|
#
# Copyright (C) 1998 - 2008, Daniel Stenberg, <daniel@haxx.se>, et al.
# Copyright (C) 1998 - 2009, Daniel Stenberg, <daniel@haxx.se>, et al.
#
# This software is licensed as described in the file COPYING, which
# you should have received as part of this distribution. The terms
@ -191,7 +191,7 @@ else
libtoolize=`findtool $LIBTOOLIZE`
fi
lt_pversion=`$libtool --version 2>/dev/null|head -n 2|sed -e 's/^[^0-9]*//g' -e 's/[- ].*//'`
lt_pversion=`$libtool --version 2>/dev/null|head -n 1|sed -e 's/^[^0-9]*//g' -e 's/[- ].*//'`
if test -z "$lt_pversion"; then
echo "buildconf: libtool not found."
echo " You need libtool version $LIBTOOL_WANTED_VERSION or newer installed"