зеркало из https://github.com/mislav/hub.git
Allow to merge with --ff-only option
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Родитель
d0c117fa7e
Коммит
06b8da85e9
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@ -27,6 +27,27 @@ Feature: hub merge
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Add `hub merge` command
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"""
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Scenario: Merge pull request with --ff-only option
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Given the GitHub API server:
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"""
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require 'json'
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get('/repos/defunkt/hub/pulls/164') { json \
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:head => {
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:label => 'jfirebaugh:hub_merge',
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:repo => {:private => false}
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},
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:title => "Add `hub merge` command"
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}
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"""
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And there is a commit named "jfirebaugh/hub_merge"
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When I successfully run `hub merge --ff-only https://github.com/defunkt/hub/pull/164`
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Then "git fetch git://github.com/jfirebaugh/hub.git +refs/heads/hub_merge:refs/remotes/jfirebaugh/hub_merge" should be run
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When I successfully run `git show -s --format=%B`
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Then the output should contain:
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"""
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Fast-forward (no commit created; -m option ignored)
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"""
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Scenario: Merge private pull request
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Given the GitHub API server:
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"""
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@ -443,8 +443,9 @@ module Hub
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idx = args.index url_arg
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args.delete_at idx
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args.insert idx, merge_head, '--no-ff', '-m',
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"Merge pull request ##{pull_id} from #{merge_head}\n\n#{pull_data['title']}"
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args.insert idx, merge_head, '-m', "Merge pull request ##{pull_id} from #{merge_head}\n\n#{pull_data['title']}"
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idx = args.index '-m'
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args.insert idx, '--no-ff' unless args.include?('--ff-only')
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end
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end
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