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[Bug #20453] segfault in Regexp timeout
https://bugs.ruby-lang.org/issues/20228 started freeing `stk_base` to avoid a memory leak. But `stk_base` is sometimes stack allocated (using `xalloca`), so the free only works if the regex stack has grown enough to hit `stack_double` (which uses `xmalloc` and `xrealloc`). To reproduce the problem on master and 3.3.1: ```ruby Regexp.timeout = 0.001 /^(a*)x$/ =~ "a" * 1000000 + "x"' ``` Some details about this potential fix: `stk_base == stk_alloc` on [init](dde99215f2/regexec.c (L1153)
), so if `stk_base != stk_alloc` we can be sure we called [`stack_double`](dde99215f2/regexec.c (L1210)
) and it's safe to free. It's also safe to free if we've [saved](dde99215f2/regexec.c (L1187-L1189)
) the stack to `msa->stack_p`, since we do the `stk_base != stk_alloc` check before saving. This matches the check we do inside [`stack_double`](dde99215f2/regexec.c (L1221)
)
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@ -4218,7 +4218,8 @@ match_at(regex_t* reg, const UChar* str, const UChar* end,
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timeout:
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xfree(xmalloc_base);
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xfree(stk_base);
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if (stk_base != stk_alloc || IS_NOT_NULL(msa->stack_p))
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xfree(stk_base);
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HANDLE_REG_TIMEOUT_IN_MATCH_AT;
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}
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@ -1827,6 +1827,17 @@ class TestRegexp < Test::Unit::TestCase
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end;
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end
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def test_bug_20453
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assert_separately([], "#{<<-"begin;"}\n#{<<-'end;'}")
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begin;
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Regexp.timeout = 0.001
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assert_raise(Regexp::TimeoutError) do
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/^(a*)x$/ =~ "a" * 1000000 + "x"
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end
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end;
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end
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def per_instance_redos_test(global_timeout, per_instance_timeout, expected_timeout)
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assert_separately([], "#{<<-"begin;"}\n#{<<-'end;'}")
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global_timeout = #{ EnvUtil.apply_timeout_scale(global_timeout).inspect }
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