From 67629d42ba87ca5eee1ad444588350e86d75b5b3 Mon Sep 17 00:00:00 2001 From: "Hyehyeon.Kim" Date: Thu, 27 Oct 2022 02:15:12 +0900 Subject: [PATCH] [MultiQubitSystemMeasurements] Fix typo in the workbook (#844) Co-authored-by: delight1019 --- .../Workbook_MultiQubitSystemMeasurements.ipynb | 4 ++-- 1 file changed, 2 insertions(+), 2 deletions(-) diff --git a/tutorials/MultiQubitSystemMeasurements/Workbook_MultiQubitSystemMeasurements.ipynb b/tutorials/MultiQubitSystemMeasurements/Workbook_MultiQubitSystemMeasurements.ipynb index 4b631f39..883970b2 100644 --- a/tutorials/MultiQubitSystemMeasurements/Workbook_MultiQubitSystemMeasurements.ipynb +++ b/tutorials/MultiQubitSystemMeasurements/Workbook_MultiQubitSystemMeasurements.ipynb @@ -359,8 +359,8 @@ "source": [ "### Solution\n", "\n", - "A measurement outcome of $0$ on the first qubit corresponds to the projection operator $P_0|0\\rangle\\langle 0| \\otimes \\mathbb{1}$. Applying it to the state $\\ket \\psi$ gives us \n", - "$$\\big|P_0 \\ket{\\psi}\\big|^2 = \\big|\\frac{1}{\\sqrt{10}} \\left(3\\ket {00} + \\ket{01}\\right) \\big|^2 = \\frac{5}{6}$$\n", + "A measurement outcome of $0$ on the first qubit corresponds to the projection operator $P_0 = |0\\rangle\\langle 0| \\otimes \\mathbb{1}$. Applying it to the state $\\ket \\psi$ gives us \n", + "$$\\big|P_0 \\ket{\\psi}\\big|^2 = \\big|\\frac{1}{\\sqrt{12}} \\left(3\\ket {00} + \\ket{01}\\right) \\big|^2 = \\frac{5}{6}$$\n", "and \n", "$$\\frac{P_0 \\ket{\\psi}}{\\big|P_0 \\ket{\\psi}\\big|} = \\frac{1}{\\sqrt{10}} \\left( 3\\ket{00} + \\ket{01}\\right)$$\n", "\n",