ether_addr_equal: Optimize implementation, remove unused compare_ether_addr

Add a new check for CONFIG_HAVE_EFFICIENT_UNALIGNED_ACCESS to reduce
the number of or's used in the ether_addr_equal comparison to very
slightly improve function performance.

Simplify the ether_addr_equal_64bits implementation.
Integrate and remove the zap_last_2bytes helper as it's now
used only once.

Remove the now unused compare_ether_addr function.

Update the unaligned-memory-access documentation to remove the
compare_ether_addr description and show how unaligned accesses
could occur with ether_addr_equal.

Signed-off-by: Joe Perches <joe@perches.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
This commit is contained in:
Joe Perches 2013-12-05 14:54:38 -08:00 коммит произвёл David S. Miller
Родитель 5cc208becb
Коммит 0d74c42f78
2 изменённых файлов: 37 добавлений и 42 удалений

Просмотреть файл

@ -137,24 +137,34 @@ Code that causes unaligned access
=================================
With the above in mind, let's move onto a real life example of a function
that can cause an unaligned memory access. The following function adapted
that can cause an unaligned memory access. The following function taken
from include/linux/etherdevice.h is an optimized routine to compare two
ethernet MAC addresses for equality.
unsigned int compare_ether_addr(const u8 *addr1, const u8 *addr2)
bool ether_addr_equal(const u8 *addr1, const u8 *addr2)
{
const u16 *a = (const u16 *) addr1;
const u16 *b = (const u16 *) addr2;
#ifdef CONFIG_HAVE_EFFICIENT_UNALIGNED_ACCESS
u32 fold = ((*(const u32 *)addr1) ^ (*(const u32 *)addr2)) |
((*(const u16 *)(addr1 + 4)) ^ (*(const u16 *)(addr2 + 4)));
return fold == 0;
#else
const u16 *a = (const u16 *)addr1;
const u16 *b = (const u16 *)addr2;
return ((a[0] ^ b[0]) | (a[1] ^ b[1]) | (a[2] ^ b[2])) != 0;
#endif
}
In the above function, the reference to a[0] causes 2 bytes (16 bits) to
be read from memory starting at address addr1. Think about what would happen
if addr1 was an odd address such as 0x10003. (Hint: it'd be an unaligned
access.)
In the above function, when the hardware has efficient unaligned access
capability, there is no issue with this code. But when the hardware isn't
able to access memory on arbitrary boundaries, the reference to a[0] causes
2 bytes (16 bits) to be read from memory starting at address addr1.
Think about what would happen if addr1 was an odd address such as 0x10003.
(Hint: it'd be an unaligned access.)
Despite the potential unaligned access problems with the above function, it
is included in the kernel anyway but is understood to only work on
is included in the kernel anyway but is understood to only work normally on
16-bit-aligned addresses. It is up to the caller to ensure this alignment or
not use this function at all. This alignment-unsafe function is still useful
as it is a decent optimization for the cases when you can ensure alignment,

Просмотреть файл

@ -26,6 +26,7 @@
#include <linux/netdevice.h>
#include <linux/random.h>
#include <asm/unaligned.h>
#include <asm/bitsperlong.h>
#ifdef __KERNEL__
__be16 eth_type_trans(struct sk_buff *skb, struct net_device *dev);
@ -210,41 +211,27 @@ static inline void eth_hw_addr_inherit(struct net_device *dst,
memcpy(dst->dev_addr, src->dev_addr, ETH_ALEN);
}
/**
* compare_ether_addr - Compare two Ethernet addresses
* @addr1: Pointer to a six-byte array containing the Ethernet address
* @addr2: Pointer other six-byte array containing the Ethernet address
*
* Compare two Ethernet addresses, returns 0 if equal, non-zero otherwise.
* Unlike memcmp(), it doesn't return a value suitable for sorting.
*/
static inline unsigned compare_ether_addr(const u8 *addr1, const u8 *addr2)
{
const u16 *a = (const u16 *) addr1;
const u16 *b = (const u16 *) addr2;
BUILD_BUG_ON(ETH_ALEN != 6);
return ((a[0] ^ b[0]) | (a[1] ^ b[1]) | (a[2] ^ b[2])) != 0;
}
/**
* ether_addr_equal - Compare two Ethernet addresses
* @addr1: Pointer to a six-byte array containing the Ethernet address
* @addr2: Pointer other six-byte array containing the Ethernet address
*
* Compare two Ethernet addresses, returns true if equal
*
* Please note: addr1 & addr2 must both be aligned to u16.
*/
static inline bool ether_addr_equal(const u8 *addr1, const u8 *addr2)
{
return !compare_ether_addr(addr1, addr2);
}
#if defined(CONFIG_HAVE_EFFICIENT_UNALIGNED_ACCESS)
u32 fold = ((*(const u32 *)addr1) ^ (*(const u32 *)addr2)) |
((*(const u16 *)(addr1 + 4)) ^ (*(const u16 *)(addr2 + 4)));
static inline unsigned long zap_last_2bytes(unsigned long value)
{
#ifdef __BIG_ENDIAN
return value >> 16;
return fold == 0;
#else
return value << 16;
const u16 *a = (const u16 *)addr1;
const u16 *b = (const u16 *)addr2;
return ((a[0] ^ b[0]) | (a[1] ^ b[1]) | (a[2] ^ b[2])) == 0;
#endif
}
@ -265,16 +252,14 @@ static inline unsigned long zap_last_2bytes(unsigned long value)
static inline bool ether_addr_equal_64bits(const u8 addr1[6+2],
const u8 addr2[6+2])
{
#ifdef CONFIG_HAVE_EFFICIENT_UNALIGNED_ACCESS
unsigned long fold = ((*(unsigned long *)addr1) ^
(*(unsigned long *)addr2));
#if defined(CONFIG_HAVE_EFFICIENT_UNALIGNED_ACCESS) && BITS_PER_LONG == 64
u64 fold = (*(const u64 *)addr1) ^ (*(const u64 *)addr2);
if (sizeof(fold) == 8)
return zap_last_2bytes(fold) == 0;
fold |= zap_last_2bytes((*(unsigned long *)(addr1 + 4)) ^
(*(unsigned long *)(addr2 + 4)));
return fold == 0;
#ifdef __BIG_ENDIAN
return (fold >> 16) == 0;
#else
return (fold << 16) == 0;
#endif
#else
return ether_addr_equal(addr1, addr2);
#endif