wimax/i2400m: use struct_size() helper

One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:

struct foo {
    int stuff;
    void *entry[];
};

size = sizeof(struct foo) + count * sizeof(void *);
instance = alloc(size, GFP_KERNEL);

Instead of leaving these open-coded and prone to type mistakes, we can
now use the new struct_size() helper:

size = struct_size(instance, entry, count);

This code was detected with the help of Coccinelle.

Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
This commit is contained in:
Gustavo A. R. Silva 2019-02-07 21:22:17 -06:00 коммит произвёл David S. Miller
Родитель a3deec5b3f
Коммит 13644be211
1 изменённых файлов: 2 добавлений и 2 удалений

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@ -1260,8 +1260,8 @@ int i2400m_rx(struct i2400m *i2400m, struct sk_buff *skb)
goto error_msg_hdr_check;
result = -EIO;
num_pls = le16_to_cpu(msg_hdr->num_pls);
pl_itr = sizeof(*msg_hdr) + /* Check payload descriptor(s) */
num_pls * sizeof(msg_hdr->pld[0]);
/* Check payload descriptor(s) */
pl_itr = struct_size(msg_hdr, pld, num_pls);
pl_itr = ALIGN(pl_itr, I2400M_PL_ALIGN);
if (pl_itr > skb_len) { /* got all the payload descriptors? */
dev_err(dev, "RX: HW BUG? message too short (%u bytes) for "