s390/bitops: remove 31 bit related comments
Signed-off-by: Heiko Carstens <heiko.carstens@de.ibm.com> Signed-off-by: Martin Schwidefsky <schwidefsky@de.ibm.com>
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@ -11,30 +11,25 @@
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* big-endian system because, unlike little endian, the number of each
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* big-endian system because, unlike little endian, the number of each
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* bit depends on the word size.
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* bit depends on the word size.
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*
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*
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* The bitop functions are defined to work on unsigned longs, so for an
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* The bitop functions are defined to work on unsigned longs, so the bits
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* s390x system the bits end up numbered:
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* end up numbered:
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* |63..............0|127............64|191...........128|255...........192|
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* |63..............0|127............64|191...........128|255...........192|
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* and on s390:
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* |31.....0|63....32|95....64|127...96|159..128|191..160|223..192|255..224|
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*
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*
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* There are a few little-endian macros used mostly for filesystem
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* There are a few little-endian macros used mostly for filesystem
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* bitmaps, these work on similar bit arrays layouts, but
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* bitmaps, these work on similar bit array layouts, but byte-oriented:
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* byte-oriented:
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* |7...0|15...8|23...16|31...24|39...32|47...40|55...48|63...56|
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* |7...0|15...8|23...16|31...24|39...32|47...40|55...48|63...56|
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*
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*
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* The main difference is that bit 3-5 (64b) or 3-4 (32b) in the bit
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* The main difference is that bit 3-5 in the bit number field needs to be
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* number field needs to be reversed compared to the big-endian bit
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* reversed compared to the big-endian bit fields. This can be achieved by
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* fields. This can be achieved by XOR with 0x38 (64b) or 0x18 (32b).
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* XOR with 0x38.
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*
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*
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* We also have special functions which work with an MSB0 encoding:
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* We also have special functions which work with an MSB0 encoding.
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* on an s390x system the bits are numbered:
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* The bits are numbered:
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* |0..............63|64............127|128...........191|192...........255|
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* |0..............63|64............127|128...........191|192...........255|
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* and on s390:
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* |0.....31|32....63|64....95|96...127|128..159|160..191|192..223|224..255|
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*
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*
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* The main difference is that bit 0-63 (64b) or 0-31 (32b) in the bit
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* The main difference is that bit 0-63 in the bit number field needs to be
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* number field needs to be reversed compared to the LSB0 encoded bit
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* reversed compared to the LSB0 encoded bit fields. This can be achieved by
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* fields. This can be achieved by XOR with 0x3f (64b) or 0x1f (32b).
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* XOR with 0x3f.
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*
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*
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*/
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*/
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@ -299,10 +294,8 @@ static inline void __clear_bit_unlock(unsigned long nr,
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/*
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/*
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* Functions which use MSB0 bit numbering.
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* Functions which use MSB0 bit numbering.
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* On an s390x system the bits are numbered:
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* The bits are numbered:
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* |0..............63|64............127|128...........191|192...........255|
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* |0..............63|64............127|128...........191|192...........255|
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* and on s390:
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* |0.....31|32....63|64....95|96...127|128..159|160..191|192..223|224..255|
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*/
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*/
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unsigned long find_first_bit_inv(const unsigned long *addr, unsigned long size);
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unsigned long find_first_bit_inv(const unsigned long *addr, unsigned long size);
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unsigned long find_next_bit_inv(const unsigned long *addr, unsigned long size,
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unsigned long find_next_bit_inv(const unsigned long *addr, unsigned long size,
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@ -1,10 +1,8 @@
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/*
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/*
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* MSB0 numbered special bitops handling.
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* MSB0 numbered special bitops handling.
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*
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*
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* On s390x the bits are numbered:
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* The bits are numbered:
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* |0..............63|64............127|128...........191|192...........255|
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* |0..............63|64............127|128...........191|192...........255|
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* and on s390:
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* |0.....31|32....63|64....95|96...127|128..159|160..191|192..223|224..255|
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*
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*
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* The reason for this bit numbering is the fact that the hardware sets bits
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* The reason for this bit numbering is the fact that the hardware sets bits
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* in a bitmap starting at bit 0 (MSB) and we don't want to scan the bitmap
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* in a bitmap starting at bit 0 (MSB) and we don't want to scan the bitmap
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