[CRYPTO] cbc: Require block size to be a power of 2
All common block ciphers have a block size that's a power of 2. In fact, all of our block ciphers obey this rule. If we require this then CBC can be optimised to avoid an expensive divide on in-place decryption. I've also changed the saving of the first IV in the in-place decryption case to the last IV because that lets us use walk->iv (which is already aligned) for the xor operation where alignment is required. Signed-off-by: Herbert Xu <herbert@gondor.apana.org.au>
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3c7f076da5
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50b6544e13
18
crypto/cbc.c
18
crypto/cbc.c
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@ -14,6 +14,7 @@
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#include <linux/err.h>
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#include <linux/init.h>
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#include <linux/kernel.h>
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#include <linux/log2.h>
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#include <linux/module.h>
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#include <linux/scatterlist.h>
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#include <linux/slab.h>
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@ -143,17 +144,13 @@ static int crypto_cbc_decrypt_inplace(struct blkcipher_desc *desc,
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void (*fn)(struct crypto_tfm *, u8 *, const u8 *) =
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crypto_cipher_alg(tfm)->cia_decrypt;
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int bsize = crypto_cipher_blocksize(tfm);
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unsigned long alignmask = crypto_cipher_alignmask(tfm);
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unsigned int nbytes = walk->nbytes;
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u8 *src = walk->src.virt.addr;
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u8 stack[bsize + alignmask];
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u8 *first_iv = (u8 *)ALIGN((unsigned long)stack, alignmask + 1);
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memcpy(first_iv, walk->iv, bsize);
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u8 last_iv[bsize];
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/* Start of the last block. */
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src += nbytes - nbytes % bsize - bsize;
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memcpy(walk->iv, src, bsize);
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src += nbytes - (nbytes & (bsize - 1)) - bsize;
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memcpy(last_iv, src, bsize);
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for (;;) {
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fn(crypto_cipher_tfm(tfm), src, src);
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@ -163,7 +160,8 @@ static int crypto_cbc_decrypt_inplace(struct blkcipher_desc *desc,
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src -= bsize;
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}
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crypto_xor(src, first_iv, bsize);
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crypto_xor(src, walk->iv, bsize);
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memcpy(walk->iv, last_iv, bsize);
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return nbytes;
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}
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@ -228,6 +226,10 @@ static struct crypto_instance *crypto_cbc_alloc(struct rtattr **tb)
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if (IS_ERR(alg))
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return ERR_PTR(PTR_ERR(alg));
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inst = ERR_PTR(-EINVAL);
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if (!is_power_of_2(alg->cra_blocksize))
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goto out_put_alg;
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inst = crypto_alloc_instance("cbc", alg);
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if (IS_ERR(inst))
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goto out_put_alg;
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