kvm: update_memslots: drop not needed check for the same number of pages
if number of pages haven't changed sorting algorithm will do nothing, so there is no need to do extra check to avoid entering sorting logic. Signed-off-by: Igor Mammedov <imammedo@redhat.com> Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>
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45c3094a64
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@ -679,21 +679,19 @@ static void update_memslots(struct kvm_memslots *slots,
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struct kvm_memory_slot *mslots = slots->memslots;
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WARN_ON(mslots[i].id != id);
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if (new->npages != mslots[i].npages) {
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if (new->npages < mslots[i].npages) {
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while (i < KVM_MEM_SLOTS_NUM - 1 &&
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new->npages < mslots[i + 1].npages) {
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mslots[i] = mslots[i + 1];
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slots->id_to_index[mslots[i].id] = i;
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i++;
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}
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} else {
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while (i > 0 &&
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new->npages > mslots[i - 1].npages) {
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mslots[i] = mslots[i - 1];
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slots->id_to_index[mslots[i].id] = i;
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i--;
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}
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if (new->npages < mslots[i].npages) {
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while (i < KVM_MEM_SLOTS_NUM - 1 &&
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new->npages < mslots[i + 1].npages) {
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mslots[i] = mslots[i + 1];
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slots->id_to_index[mslots[i].id] = i;
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i++;
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}
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} else {
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while (i > 0 &&
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new->npages > mslots[i - 1].npages) {
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mslots[i] = mslots[i - 1];
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slots->id_to_index[mslots[i].id] = i;
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i--;
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}
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}
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