iommu: Print default domain type on boot

Introduce a subsys_initcall for IOMMU code and use it to
print the default domain type at boot.

Signed-off-by: Joerg Roedel <jroedel@suse.de>
This commit is contained in:
Joerg Roedel 2019-08-19 15:22:53 +02:00
Родитель 74bc0f6b22
Коммит 5fa9e7c5fa
1 изменённых файлов: 29 добавлений и 1 удалений

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@ -93,12 +93,40 @@ struct iommu_group_attribute iommu_group_attr_##_name = \
static LIST_HEAD(iommu_device_list);
static DEFINE_SPINLOCK(iommu_device_lock);
/*
* Use a function instead of an array here because the domain-type is a
* bit-field, so an array would waste memory.
*/
static const char *iommu_domain_type_str(unsigned int t)
{
switch (t) {
case IOMMU_DOMAIN_BLOCKED:
return "Blocked";
case IOMMU_DOMAIN_IDENTITY:
return "Passthrough";
case IOMMU_DOMAIN_UNMANAGED:
return "Unmanaged";
case IOMMU_DOMAIN_DMA:
return "Translated";
default:
return "Unknown";
}
}
static int __init iommu_subsys_init(void)
{
pr_info("Default domain type: %s\n",
iommu_domain_type_str(iommu_def_domain_type));
return 0;
}
subsys_initcall(iommu_subsys_init);
int iommu_device_register(struct iommu_device *iommu)
{
spin_lock(&iommu_device_lock);
list_add_tail(&iommu->list, &iommu_device_list);
spin_unlock(&iommu_device_lock);
return 0;
}