mptcp: avoid unneeded __mptcp_nmpc_socket() usage
In a few spots, the mptcp code invokes the __mptcp_nmpc_socket() helper multiple times under the same socket lock scope. Additionally, in such places, the socket status ensures that there is no MP capable handshake running. Under the above condition we can replace the later __mptcp_nmpc_socket() helper invocation with direct access to the msk->subflow pointer and better document such access is not supposed to fail with WARN(). Signed-off-by: Paolo Abeni <pabeni@redhat.com> Reviewed-by: Matthieu Baerts <matthieu.baerts@tessares.net> Signed-off-by: Matthieu Baerts <matthieu.baerts@tessares.net> Signed-off-by: David S. Miller <davem@davemloft.net>
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7a486c443c
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6176123169
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@ -3143,7 +3143,7 @@ static struct sock *mptcp_accept(struct sock *sk, int flags, int *err,
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struct socket *listener;
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struct sock *newsk;
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listener = __mptcp_nmpc_socket(msk);
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listener = msk->subflow;
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if (WARN_ON_ONCE(!listener)) {
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*err = -EINVAL;
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return NULL;
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@ -3363,7 +3363,7 @@ static int mptcp_get_port(struct sock *sk, unsigned short snum)
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struct mptcp_sock *msk = mptcp_sk(sk);
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struct socket *ssock;
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ssock = __mptcp_nmpc_socket(msk);
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ssock = msk->subflow;
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pr_debug("msk=%p, subflow=%p", msk, ssock);
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if (WARN_ON_ONCE(!ssock))
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return -EINVAL;
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@ -3709,7 +3709,10 @@ static int mptcp_stream_accept(struct socket *sock, struct socket *newsock,
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pr_debug("msk=%p", msk);
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ssock = __mptcp_nmpc_socket(msk);
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/* buggy applications can call accept on socket states other then LISTEN
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* but no need to allocate the first subflow just to error out.
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*/
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ssock = msk->subflow;
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if (!ssock)
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return -EINVAL;
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