ARM: Fix sparsemem with SPARSEMEM_EXTREME enabled
When SPARSEMEM_EXTREME is enabled, memory_present() wants to use bootmem to allocate data structures. However, we call memory_present() after declaring memory to bootmem, but before we've reserved areas. This leads to sparsemem data structures being overwritten later in the kernel's initialization (when slab initializes.) Signed-off-by: Russell King <rmk+kernel@arm.linux.org.uk>
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Родитель
c06e004c72
Коммит
657e12fd38
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@ -273,7 +273,6 @@ static void __init bootmem_init_node(int node, struct meminfo *mi,
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struct membank *bank = &mi->bank[i];
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if (!bank->highmem)
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free_bootmem_node(pgdat, bank_phys_start(bank), bank_phys_size(bank));
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memory_present(node, bank_pfn_start(bank), bank_pfn_end(bank));
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}
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/*
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@ -370,6 +369,19 @@ int pfn_valid(unsigned long pfn)
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return 0;
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}
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EXPORT_SYMBOL(pfn_valid);
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static void arm_memory_present(struct meminfo *mi, int node)
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{
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}
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#else
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static void arm_memory_present(struct meminfo *mi, int node)
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{
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int i;
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for_each_nodebank(i, mi, node) {
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struct membank *bank = &mi->bank[i];
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memory_present(node, bank_pfn_start(bank), bank_pfn_end(bank));
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}
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}
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#endif
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static int __init meminfo_cmp(const void *_a, const void *_b)
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@ -427,6 +439,12 @@ void __init bootmem_init(void)
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*/
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if (node == initrd_node)
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bootmem_reserve_initrd(node);
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/*
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* Sparsemem tries to allocate bootmem in memory_present(),
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* so must be done after the fixed reservations
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*/
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arm_memory_present(mi, node);
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}
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/*
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