sctp: hold the chunks only after the chunk is enqueued in outq
When a msg is sent, sctp will hold the chunks of this msg and then try to enqueue them. But if the chunks are not enqueued in sctp_outq_tail() because of the invalid state, sctp_cmd_interpreter() may still return success to sctp_sendmsg() after calling sctp_outq_flush(), these chunks will become orphans and will leak. So we fix them by moving sctp_chunk_hold() to sctp_outq_tail(), where we are sure that the chunk is going to get queued. Signed-off-by: Xin Long <lucien.xin@gmail.com> Signed-off-by: Marcelo Ricardo Leitner <marcelo.leitner@gmail.com> Signed-off-by: David S. Miller <davem@davemloft.net>
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@ -324,6 +324,7 @@ int sctp_outq_tail(struct sctp_outq *q, struct sctp_chunk *chunk)
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sctp_cname(SCTP_ST_CHUNK(chunk->chunk_hdr->type)) :
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"illegal chunk");
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sctp_chunk_hold(chunk);
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sctp_outq_tail_data(q, chunk);
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if (chunk->chunk_hdr->flags & SCTP_DATA_UNORDERED)
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SCTP_INC_STATS(net, SCTP_MIB_OUTUNORDERCHUNKS);
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@ -1952,8 +1952,6 @@ static int sctp_sendmsg(struct sock *sk, struct msghdr *msg, size_t msg_len)
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/* Now send the (possibly) fragmented message. */
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list_for_each_entry(chunk, &datamsg->chunks, frag_list) {
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sctp_chunk_hold(chunk);
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/* Do accounting for the write space. */
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sctp_set_owner_w(chunk);
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