samples/bpf: Extend RLIMIT_MEMLOCK for xdp_{sample_pkts, router_ipv4}
There is a common problem with xdp samples that happens when user wants to run a particular sample and some bpf program is already loaded. The default 64kb RLIMIT_MEMLOCK resource limit will cause a following error (assuming that xdp sample that is failing was converted to libbpf usage): libbpf: Error in bpf_object__probe_name():Operation not permitted(1). Couldn't load basic 'r0 = 0' BPF program. libbpf: failed to load object './xdp_sample_pkts_kern.o' Fix it in xdp_sample_pkts and xdp_router_ipv4 by setting RLIMIT_MEMLOCK to RLIM_INFINITY. Signed-off-by: Maciej Fijalkowski <maciej.fijalkowski@intel.com> Reviewed-by: Jakub Kicinski <jakub.kicinski@netronome.com> Acked-by: Jesper Dangaard Brouer <brouer@redhat.com> Acked-by: John Fastabend <john.fastabend@gmail.com> Signed-off-by: Daniel Borkmann <daniel@iogearbox.net>
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@ -25,6 +25,7 @@
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#include <sys/syscall.h>
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#include "bpf_util.h"
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#include "bpf/libbpf.h"
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#include <sys/resource.h>
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int sock, sock_arp, flags = 0;
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static int total_ifindex;
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@ -609,6 +610,7 @@ cleanup:
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int main(int ac, char **argv)
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{
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struct rlimit r = {RLIM_INFINITY, RLIM_INFINITY};
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struct bpf_prog_load_attr prog_load_attr = {
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.prog_type = BPF_PROG_TYPE_XDP,
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};
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@ -635,6 +637,11 @@ int main(int ac, char **argv)
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ifname_list = (argv + 1);
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}
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if (setrlimit(RLIMIT_MEMLOCK, &r)) {
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perror("setrlimit(RLIMIT_MEMLOCK)");
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return 1;
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}
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if (bpf_prog_load_xattr(&prog_load_attr, &obj, &prog_fd))
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return 1;
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@ -12,6 +12,7 @@
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#include <signal.h>
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#include <libbpf.h>
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#include <bpf/bpf.h>
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#include <sys/resource.h>
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#include "perf-sys.h"
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#include "trace_helpers.h"
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@ -99,6 +100,7 @@ static void sig_handler(int signo)
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int main(int argc, char **argv)
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{
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struct rlimit r = {RLIM_INFINITY, RLIM_INFINITY};
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struct bpf_prog_load_attr prog_load_attr = {
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.prog_type = BPF_PROG_TYPE_XDP,
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};
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@ -114,6 +116,11 @@ int main(int argc, char **argv)
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return 1;
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}
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if (setrlimit(RLIMIT_MEMLOCK, &r)) {
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perror("setrlimit(RLIMIT_MEMLOCK)");
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return 1;
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}
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numcpus = get_nprocs();
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if (numcpus > MAX_CPUS)
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numcpus = MAX_CPUS;
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