AFS: Part of afs_end_call() is identical to code elsewhere, so split it

Split afs_end_call() into two pieces, one of which is identical to code in
afs_process_async_call().  Replace the latter with a call to the first part of
afs_end_call().

Signed-off-by: Nathaniel Wesley Filardo <nwf@cs.jhu.edu>
Signed-off-by: David Howells <dhowells@redhat.com>
This commit is contained in:
Nathaniel Wesley Filardo 2014-05-21 16:04:11 +01:00 коммит произвёл David Howells
Родитель 6c67c7c38c
Коммит 6cf12869f5
1 изменённых файлов: 13 добавлений и 7 удалений

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@ -184,15 +184,24 @@ static void afs_free_call(struct afs_call *call)
}
/*
* End a call
* End a call but do not free it
*/
static void afs_end_call(struct afs_call *call)
static void afs_end_call_nofree(struct afs_call *call)
{
if (call->rxcall) {
rxrpc_kernel_end_call(call->rxcall);
call->rxcall = NULL;
}
if (call->type->destructor)
call->type->destructor(call);
}
/*
* End a call and free it
*/
static void afs_end_call(struct afs_call *call)
{
afs_end_call_nofree(call);
afs_free_call(call);
}
@ -640,10 +649,7 @@ static void afs_process_async_call(struct work_struct *work)
call->reply = NULL;
/* kill the call */
rxrpc_kernel_end_call(call->rxcall);
call->rxcall = NULL;
if (call->type->destructor)
call->type->destructor(call);
afs_end_call_nofree(call);
/* we can't just delete the call because the work item may be
* queued */