[IA64] remove redundant display of free swap space in show_mem()

show_mem() has no need to print the amount of free swap space manually because
show_free_areas() does this already and is called by the former.

The two outputs only differ in text formatting:

  printk("Free swap  = %lukB\n", ...);
  printk("Free swap:       %6ldkB\n", ...);

Signed-off-by: Johannes Weiner <hannes@saeurebad.de>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Tony Luck <tony.luck@intel.com>

arch/ia64/mm/contig.c

@@ -45,8 +45,6 @@ void show_mem(void)
 
 	printk(KERN_INFO "Mem-info:\n");
 	show_free_areas();
-	printk(KERN_INFO "Free swap:       %6ldkB\n",
-	       nr_swap_pages<<(PAGE_SHIFT-10));
 	printk(KERN_INFO "Node memory in pages:\n");
 	for_each_online_pgdat(pgdat) {
 		unsigned long present;

arch/ia64/mm/discontig.c

@@ -522,8 +522,6 @@ void show_mem(void)
 
 	printk(KERN_INFO "Mem-info:\n");
 	show_free_areas();
-	printk(KERN_INFO "Free swap:       %6ldkB\n",
-	       nr_swap_pages<<(PAGE_SHIFT-10));
 	printk(KERN_INFO "Node memory in pages:\n");
 	for_each_online_pgdat(pgdat) {
 		unsigned long present;