sched, sysctl: Delete an unnecessary check before unregister_sysctl_table()

The unregister_sysctl_table() function tests whether its argument is NULL
and then returns immediately. Thus the test around the call is not needed.

This issue was detected by using the Coccinelle software.

Signed-off-by: Markus Elfring <elfring@users.sourceforge.net>
Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Mike Galbraith <efault@gmx.de>
Cc: Peter Zijlstra <peterz@infradead.org>
Cc: Thomas Gleixner <tglx@linutronix.de>
Link: http://lkml.kernel.org/r/5597877E.3060503@users.sourceforge.net
Signed-off-by: Ingo Molnar <mingo@kernel.org>
This commit is contained in:
Markus Elfring 2015-07-04 09:06:32 +02:00 коммит произвёл Ingo Molnar
Родитель 3fe33bcdd3
Коммит 781b020342
1 изменённых файлов: 1 добавлений и 2 удалений

Просмотреть файл

@ -5311,7 +5311,6 @@ static void register_sched_domain_sysctl(void)
/* may be called multiple times per register */ /* may be called multiple times per register */
static void unregister_sched_domain_sysctl(void) static void unregister_sched_domain_sysctl(void)
{ {
if (sd_sysctl_header)
unregister_sysctl_table(sd_sysctl_header); unregister_sysctl_table(sd_sysctl_header);
sd_sysctl_header = NULL; sd_sysctl_header = NULL;
if (sd_ctl_dir[0].child) if (sd_ctl_dir[0].child)