spi: Dont call prepare/unprepare transfer if not populated

Currently the prepare/unprepare transfer are called unconditionally.
The assumption is that every driver using the spi core queue infrastructure
has to populate the prepare and unprepare functions. This encourages
drivers to populate empty functions to prevent crashing.
This patch prevents the call to prepare/unprepare if not populated.

Signed-off-by: Shubhrajyoti D <shubhrajyoti@ti.com>
Acked-by: Linus Walleij <linus.walleij@linaro.org>
[grant.likely: fix whitespace defect]
Signed-off-by: Grant Likely <grant.likely@secretlab.ca>
This commit is contained in:
Shubhrajyoti D 2012-05-10 19:20:41 +05:30 коммит произвёл Grant Likely
Родитель 6d6467ee58
Коммит 7dfd2bd702
1 изменённых файлов: 2 добавлений и 2 удалений

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@ -532,7 +532,7 @@ static void spi_pump_messages(struct kthread_work *work)
/* Lock queue and check for queue work */
spin_lock_irqsave(&master->queue_lock, flags);
if (list_empty(&master->queue) || !master->running) {
if (master->busy) {
if (master->busy && master->unprepare_transfer_hardware) {
ret = master->unprepare_transfer_hardware(master);
if (ret) {
spin_unlock_irqrestore(&master->queue_lock, flags);
@ -562,7 +562,7 @@ static void spi_pump_messages(struct kthread_work *work)
master->busy = true;
spin_unlock_irqrestore(&master->queue_lock, flags);
if (!was_busy) {
if (!was_busy && master->prepare_transfer_hardware) {
ret = master->prepare_transfer_hardware(master);
if (ret) {
dev_err(&master->dev,