bcache: not use hard coded memset size in bch_cache_accounting_clear()

In stats.c:bch_cache_accounting_clear(), a hard coded number '7' is
used in memset(). It is because in struct cache_stats, there are 7
atomic_t type members. This is not good when new members added into
struct stats, the hard coded number will only clear part of memory.

This patch replaces 'sizeof(unsigned long) * 7' by more generic
'sizeof(struct cache_stats))', to avoid potential error if new
member added into struct cache_stats.

Signed-off-by: Coly Li <colyli@suse.de>
Signed-off-by: Jens Axboe <axboe@kernel.dk>
This commit is contained in:
Coly Li 2019-02-09 12:52:54 +08:00 коммит произвёл Jens Axboe
Родитель 9951379b0c
Коммит 83ff9318c4
1 изменённых файлов: 1 добавлений и 1 удалений

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@ -111,7 +111,7 @@ void bch_cache_accounting_clear(struct cache_accounting *acc)
{
memset(&acc->total.cache_hits,
0,
sizeof(unsigned long) * 7);
sizeof(struct cache_stats));
}
void bch_cache_accounting_destroy(struct cache_accounting *acc)