libceph: avoid dropping con mutex before fault

The ceph_fault() function takes the con mutex, so we should avoid
dropping it before calling it.  This fixes a potential race with
another thread calling ceph_con_close(), or _open(), or similar (we
don't reverify con->state after retaking the lock).

Add annotation so that lockdep realizes we will drop the mutex before
returning.

Signed-off-by: Sage Weil <sage@inktank.com>
Reviewed-by: Alex Elder <elder@inktank.com>
This commit is contained in:
Sage Weil 2012-07-30 18:17:13 -07:00
Родитель 7b862e07b1
Коммит 8636ea672f
1 изменённых файлов: 1 добавлений и 3 удалений

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@ -2336,7 +2336,6 @@ done_unlocked:
return;
fault:
mutex_unlock(&con->mutex);
ceph_fault(con); /* error/fault path */
goto done_unlocked;
}
@ -2347,9 +2346,8 @@ fault:
* exponential backoff
*/
static void ceph_fault(struct ceph_connection *con)
__releases(con->mutex)
{
mutex_lock(&con->mutex);
pr_err("%s%lld %s %s\n", ENTITY_NAME(con->peer_name),
ceph_pr_addr(&con->peer_addr.in_addr), con->error_msg);
dout("fault %p state %lu to peer %s\n",