cifs: fix handling of scopeid in cifs_convert_address
The code finds, the '%' sign in an ipv6 address and copies that to a buffer allocated on the stack. It then ignores that buffer, and passes 'pct' to simple_strtoul(), which doesn't work right because we're comparing 'endp' against a completely different string. Fix it by passing the correct pointer. While we're at it, this is a good candidate for conversion to strict_strtoul as well. Cc: stable@kernel.org Cc: David Howells <dhowells@redhat.com> Reported-by: Björn JACKE <bj@sernet.de> Signed-off-by: Jeff Layton <jlayton@redhat.com> Signed-off-by: Steve French <sfrench@us.ibm.com>
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a2640111d5
Коммит
9616125611
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@ -170,7 +170,7 @@ cifs_convert_address(struct sockaddr *dst, const char *src, int len)
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{
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int rc, alen, slen;
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const char *pct;
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char *endp, scope_id[13];
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char scope_id[13];
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struct sockaddr_in *s4 = (struct sockaddr_in *) dst;
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struct sockaddr_in6 *s6 = (struct sockaddr_in6 *) dst;
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@ -197,9 +197,9 @@ cifs_convert_address(struct sockaddr *dst, const char *src, int len)
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memcpy(scope_id, pct + 1, slen);
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scope_id[slen] = '\0';
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s6->sin6_scope_id = (u32) simple_strtoul(pct, &endp, 0);
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if (endp != scope_id + slen)
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return 0;
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rc = strict_strtoul(scope_id, 0,
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(unsigned long *)&s6->sin6_scope_id);
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rc = (rc == 0) ? 1 : 0;
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}
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return rc;
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