hpsa: notice all request_irq errors
In MSI and MSI-X mode, where hpsa asks for more than one interrupt, hpsa_request_irqs forgets if the first request_irq call failed if later ones succeed. It needs to exit the loop on any failure rather than continue, freeing all irqs that were requested until that point. Also, it needs to clear out the q numbers up to MAX_REPLY_QUEUES. The same is true for the general hpsa_free_irqs function. Tested with error injection of -ENOSYS on the 4th call: [ 9.277691] injecting error in inj_request_irq: 1 4 [ 9.277780] hpsa 0000:02:00.0: failed to get irq 35 for hpsa1 [ 10.711623] scsi host1: Error handler scsi_eh_1 exiting [ 10.739170] hpsa: probe of 0000:02:00.0 failed with error -38 Reviewed-by: Scott Teel <scott.teel@pmcs.com> Signed-off-by: Robert Elliott <elliott@hp.com> Signed-off-by: Don Brace <don.brace@pmcs.com> Signed-off-by: Christoph Hellwig <hch@lst.de>
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@ -6508,6 +6508,8 @@ static void hpsa_free_irqs(struct ctlr_info *h)
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irq_set_affinity_hint(h->intr[i], NULL);
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free_irq(h->intr[i], &h->q[i]);
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}
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for (; i < MAX_REPLY_QUEUES; i++)
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h->q[i] = 0;
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}
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static int hpsa_request_irq(struct ctlr_info *h,
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@ -6525,10 +6527,25 @@ static int hpsa_request_irq(struct ctlr_info *h,
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if (h->intr_mode == PERF_MODE_INT && h->msix_vector > 0) {
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/* If performant mode and MSI-X, use multiple reply queues */
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for (i = 0; i < h->msix_vector; i++)
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for (i = 0; i < h->msix_vector; i++) {
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rc = request_irq(h->intr[i], msixhandler,
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0, h->devname,
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&h->q[i]);
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if (rc) {
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int j;
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dev_err(&h->pdev->dev,
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"failed to get irq %d for %s\n",
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h->intr[i], h->devname);
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for (j = 0; j < i; j++) {
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free_irq(h->intr[j], &h->q[j]);
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h->q[j] = 0;
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}
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for (; j < MAX_REPLY_QUEUES; j++)
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h->q[j] = 0;
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return rc;
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}
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}
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hpsa_irq_affinity_hints(h);
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} else {
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/* Use single reply pool */
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