drm/nv50: make the blocksize depend on vram size
- This should be better than what we have now. - I'm less sure about the non power of two path. Signed-off-by: Maarten Maathuis <madman2003@gmail.com>
This commit is contained in:
Родитель
1c7059e4f3
Коммит
a510604df9
|
@ -33,6 +33,8 @@
|
||||||
#include "nouveau_drv.h"
|
#include "nouveau_drv.h"
|
||||||
#include "nouveau_dma.h"
|
#include "nouveau_dma.h"
|
||||||
|
|
||||||
|
#include <linux/log2.h>
|
||||||
|
|
||||||
static void
|
static void
|
||||||
nouveau_bo_del_ttm(struct ttm_buffer_object *bo)
|
nouveau_bo_del_ttm(struct ttm_buffer_object *bo)
|
||||||
{
|
{
|
||||||
|
@ -67,29 +69,29 @@ nouveau_bo_fixup_align(struct drm_device *dev,
|
||||||
* avoid corruption of other buffer objects.
|
* avoid corruption of other buffer objects.
|
||||||
*/
|
*/
|
||||||
if (dev_priv->card_type == NV_50) {
|
if (dev_priv->card_type == NV_50) {
|
||||||
|
uint32_t block_size = nouveau_mem_fb_amount(dev) >> 15;
|
||||||
|
int i;
|
||||||
|
|
||||||
switch (tile_flags) {
|
switch (tile_flags) {
|
||||||
case 0x1800:
|
case 0x1800:
|
||||||
case 0x2800:
|
case 0x2800:
|
||||||
case 0x4800:
|
case 0x4800:
|
||||||
case 0x7a00:
|
case 0x7a00:
|
||||||
if (dev_priv->chipset >= 0xA0) {
|
*size = roundup(*size, block_size);
|
||||||
*size = roundup(*size, 28672);
|
if (is_power_of_2(block_size)) {
|
||||||
/* This is based on high end cards with 448 bits
|
*size += 3 * block_size;
|
||||||
* memory bus, could be different elsewhere.*/
|
for (i = 1; i < 10; i++) {
|
||||||
*size += 6 * 28672;
|
*align = 12 * i * block_size;
|
||||||
/* 8 * 28672 is the actual alignment requirement
|
if (!(*align % 65536))
|
||||||
* but we must also align to page size. */
|
break;
|
||||||
*align = 2 * 8 * 28672;
|
}
|
||||||
} else if (dev_priv->chipset >= 0x90) {
|
|
||||||
*size = roundup(*size, 16384);
|
|
||||||
*size += 3 * 16384;
|
|
||||||
*align = 12 * 16384;
|
|
||||||
} else {
|
} else {
|
||||||
*size = roundup(*size, 8192);
|
*size += 6 * block_size;
|
||||||
*size += 3 * 8192;
|
for (i = 1; i < 10; i++) {
|
||||||
/* 12 * 8192 is the actual alignment requirement
|
*align = 8 * i * block_size;
|
||||||
* but we must also align to page size. */
|
if (!(*align % 65536))
|
||||||
*align = 2 * 12 * 8192;
|
break;
|
||||||
|
}
|
||||||
}
|
}
|
||||||
break;
|
break;
|
||||||
default:
|
default:
|
||||||
|
|
Загрузка…
Ссылка в новой задаче