via-cuda: Use spinlock_irq_save/restore instead of enable/disable_irq
The cuda_start() function uses spinlock_irq_save/restore for mutual exclusion. Let's have cuda_poll() do the same when polling the VIA interrupt. The benefit to disabling local irqs when the interrupt is being polled is that the interrupt handler now has the same timing properties regardless of whether it is invoked normally or from cuda_poll(). This driver was written back when local irqs remained enabled during execution of interrupt handlers and cuda_poll() was probably trying to achieve the same effect by use of enable/disable_irq. Tested-by: Stan Johnson <userm57@yahoo.com> Signed-off-by: Finn Thain <fthain@telegraphics.com.au> Signed-off-by: Michael Ellerman <mpe@ellerman.id.au>
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@ -459,14 +459,7 @@ cuda_start(void)
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void
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cuda_poll(void)
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{
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/* cuda_interrupt only takes a normal lock, we disable
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* interrupts here to avoid re-entering and thus deadlocking.
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*/
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if (cuda_irq)
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disable_irq(cuda_irq);
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cuda_interrupt(0, NULL);
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if (cuda_irq)
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enable_irq(cuda_irq);
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cuda_interrupt(0, NULL);
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}
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EXPORT_SYMBOL(cuda_poll);
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@ -475,13 +468,14 @@ EXPORT_SYMBOL(cuda_poll);
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static irqreturn_t
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cuda_interrupt(int irq, void *arg)
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{
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unsigned long flags;
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u8 status;
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struct adb_request *req = NULL;
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unsigned char ibuf[16];
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int ibuf_len = 0;
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int complete = 0;
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spin_lock(&cuda_lock);
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spin_lock_irqsave(&cuda_lock, flags);
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/* On powermacs, this handler is registered for the VIA IRQ. But they use
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* just the shift register IRQ -- other VIA interrupt sources are disabled.
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@ -494,7 +488,7 @@ cuda_interrupt(int irq, void *arg)
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#endif
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{
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if ((in_8(&via[IFR]) & SR_INT) == 0) {
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spin_unlock(&cuda_lock);
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spin_unlock_irqrestore(&cuda_lock, flags);
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return IRQ_NONE;
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} else {
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out_8(&via[IFR], SR_INT);
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@ -616,7 +610,7 @@ cuda_interrupt(int irq, void *arg)
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default:
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pr_err("cuda_interrupt: unknown cuda_state %d?\n", cuda_state);
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}
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spin_unlock(&cuda_lock);
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spin_unlock_irqrestore(&cuda_lock, flags);
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if (complete && req) {
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void (*done)(struct adb_request *) = req->done;
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mb();
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