netlink: update listeners directly when removing socket
The code is now confusing to read - first in one function down (netlink_remove) any group subscriptions are implicitly removed by calling __sk_del_bind_node(), but the subscriber database is only updated far later by calling netlink_update_listeners(). Move the latter call to just after removal from the list so it is easier to follow the code. This also enables moving the locking inside the kernel-socket conditional, which improves the normal socket destruction path. Signed-off-by: Johannes Berg <johannes.berg@intel.com> Signed-off-by: David S. Miller <davem@davemloft.net>
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@ -1091,8 +1091,10 @@ static void netlink_remove(struct sock *sk)
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mutex_unlock(&nl_sk_hash_lock);
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netlink_table_grab();
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if (nlk_sk(sk)->subscriptions)
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if (nlk_sk(sk)->subscriptions) {
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__sk_del_bind_node(sk);
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netlink_update_listeners(sk);
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}
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netlink_table_ungrab();
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}
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@ -1226,8 +1228,8 @@ static int netlink_release(struct socket *sock)
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module_put(nlk->module);
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netlink_table_grab();
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if (netlink_is_kernel(sk)) {
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netlink_table_grab();
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BUG_ON(nl_table[sk->sk_protocol].registered == 0);
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if (--nl_table[sk->sk_protocol].registered == 0) {
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struct listeners *old;
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@ -1241,10 +1243,8 @@ static int netlink_release(struct socket *sock)
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nl_table[sk->sk_protocol].flags = 0;
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nl_table[sk->sk_protocol].registered = 0;
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}
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} else if (nlk->subscriptions) {
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netlink_update_listeners(sk);
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netlink_table_ungrab();
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}
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netlink_table_ungrab();
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kfree(nlk->groups);
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nlk->groups = NULL;
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