xfs: use uuid_be to implement the uuid_t type

Use the generic Linux definition to implement our UUID type, this will
allow using more generic infrastructure in the future.

Signed-off-by: Christoph Hellwig <hch@lst.de>
Reviewed-by: Amir Goldstein <amir73il@gmail.com>
Reviewed-by: Brian Foster <bfoster@redhat.com>
Reviewed-by: Andy Shevchenko <andriy.shevchenko@linux.intel.com>
Reviewed-by: Darrick J. Wong <darrick.wong@oracle.com>
This commit is contained in:
Christoph Hellwig 2017-05-05 09:53:09 +02:00
Родитель dfd7487e99
Коммит b1f359f980
2 изменённых файлов: 3 добавлений и 4 удалений

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@ -18,10 +18,6 @@
#ifndef __XFS_SUPPORT_UUID_H__
#define __XFS_SUPPORT_UUID_H__
typedef struct {
unsigned char __u_bits[16];
} uuid_t;
extern int uuid_is_nil(uuid_t *uuid);
extern int uuid_equal(uuid_t *uuid1, uuid_t *uuid2);
extern void uuid_getnodeuniq(uuid_t *uuid, int fsid [2]);

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@ -19,6 +19,7 @@
#define __XFS_LINUX__
#include <linux/types.h>
#include <linux/uuid.h>
/*
* Kernel specific type declarations for XFS
@ -38,6 +39,8 @@ typedef __s64 xfs_daddr_t; /* <disk address> type */
typedef __u32 xfs_dev_t;
typedef __u32 xfs_nlink_t;
typedef uuid_be uuid_t;
#include "xfs_types.h"
#include "kmem.h"