parser: remove unnecessary strlen()
No functional change. Cache strlen() result to avoid recalculating it up to 3 times on the worst case. Reduces code size a little by 32 bytes: text data bss dec hex filename 1385 0 0 1385 569 lib/parser.o-BEFORE 1353 0 0 1353 549 lib/parser.o-AFTER Signed-off-by: André Goddard Rosa <andre.goddard@gmail.com> Cc: Randy Dunlap <randy.dunlap@oracle.com> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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Родитель
e7d2860b69
Коммит
b5f54b07c0
11
lib/parser.c
11
lib/parser.c
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@ -56,13 +56,16 @@ static int match_one(char *s, const char *p, substring_t args[])
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args[argc].from = s;
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args[argc].from = s;
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switch (*p++) {
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switch (*p++) {
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case 's':
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case 's': {
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if (strlen(s) == 0)
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size_t str_len = strlen(s);
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if (str_len == 0)
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return 0;
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return 0;
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else if (len == -1 || len > strlen(s))
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if (len == -1 || len > str_len)
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len = strlen(s);
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len = str_len;
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args[argc].to = s + len;
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args[argc].to = s + len;
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break;
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break;
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}
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case 'd':
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case 'd':
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simple_strtol(s, &args[argc].to, 0);
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simple_strtol(s, &args[argc].to, 0);
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goto num;
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goto num;
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