trace: branch profiling should not print percent without data

Impact: cleanup on output of branch profiler

When a branch has not been taken, it does not make sense to show
a percentage incorrect or hit. This patch changes the behaviour
to print out a 'X' when the branch has not been executed yet.

For example:

 correct incorrect  %        Function                  File              Line
 ------- ---------  -        --------                  ----              ----
    2096        0   0 do_arch_prctl                  process_64.c         832
       0        0   X do_arch_prctl                  process_64.c         804
    2604        0   0 IS_ERR                         err.h                34
  130228     5765   4 __switch_to                    process_64.c         673
       0        0   X enable_TSC                     process_64.c         448
       0        0   X disable_TSC                    process_64.c         431

Signed-off-by: Steven Rostedt <srostedt@redhat.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
This commit is contained in:
Steven Rostedt 2008-11-21 01:51:53 -05:00 коммит произвёл Ingo Molnar
Родитель 45b797492a
Коммит bac28bfe42
1 изменённых файлов: 7 добавлений и 3 удалений

Просмотреть файл

@ -225,7 +225,7 @@ static int t_show(struct seq_file *m, void *v)
{
struct ftrace_branch_data *p = v;
const char *f;
unsigned long percent;
long percent;
if (v == (void *)1) {
seq_printf(m, " correct incorrect %% "
@ -247,9 +247,13 @@ static int t_show(struct seq_file *m, void *v)
percent = p->incorrect * 100;
percent /= p->correct + p->incorrect;
} else
percent = p->incorrect ? 100 : 0;
percent = p->incorrect ? 100 : -1;
seq_printf(m, "%8lu %8lu %3lu ", p->correct, p->incorrect, percent);
seq_printf(m, "%8lu %8lu ", p->correct, p->incorrect);
if (percent < 0)
seq_printf(m, " X ");
else
seq_printf(m, "%3ld ", percent);
seq_printf(m, "%-30.30s %-20.20s %d\n", p->func, f, p->line);
return 0;
}