ia64: convert unwcheck.py to python3
Since my system use python3 as default, arch/ia64/scripts/unwcheck.py no
longer run.
This patch convert it to the python3 syntax.
I have ran it with python2/python3 while printing values of
start/end/rlen_sum which could be impacted by this change and I see no difference.
Fixes: 94a4708352
("scripts: change scripts to use system python instead of env")
Signed-off-by: Corentin Labbe <clabbe@baylibre.com>
Signed-off-by: Tony Luck <tony.luck@intel.com>
This commit is contained in:
Родитель
661e50bc85
Коммит
bd5edbe677
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@ -16,7 +16,7 @@ import re
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import sys
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if len(sys.argv) != 2:
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print "Usage: %s FILE" % sys.argv[0]
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print("Usage: %s FILE" % sys.argv[0])
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sys.exit(2)
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readelf = os.getenv("READELF", "readelf")
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@ -29,7 +29,7 @@ def check_func (func, slots, rlen_sum):
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global num_errors
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num_errors += 1
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if not func: func = "[%#x-%#x]" % (start, end)
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print "ERROR: %s: %lu slots, total region length = %lu" % (func, slots, rlen_sum)
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print("ERROR: %s: %lu slots, total region length = %lu" % (func, slots, rlen_sum))
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return
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num_funcs = 0
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@ -43,23 +43,23 @@ for line in os.popen("%s -u %s" % (readelf, sys.argv[1])):
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check_func(func, slots, rlen_sum)
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func = m.group(1)
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start = long(m.group(2), 16)
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end = long(m.group(3), 16)
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start = int(m.group(2), 16)
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end = int(m.group(3), 16)
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slots = 3 * (end - start) / 16
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rlen_sum = 0L
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rlen_sum = 0
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num_funcs += 1
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else:
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m = rlen_pattern.match(line)
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if m:
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rlen_sum += long(m.group(1))
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rlen_sum += int(m.group(1))
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check_func(func, slots, rlen_sum)
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if num_errors == 0:
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print "No errors detected in %u functions." % num_funcs
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print("No errors detected in %u functions." % num_funcs)
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else:
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if num_errors > 1:
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err="errors"
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else:
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err="error"
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print "%u %s detected in %u functions." % (num_errors, err, num_funcs)
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print("%u %s detected in %u functions." % (num_errors, err, num_funcs))
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sys.exit(1)
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