x86/fpu: Make init_fpu() static
Now that the allocation users have been split off into a separate function, init_fpu() has become local to i387.c: make it static. Reviewed-by: Borislav Petkov <bp@alien8.de> Cc: Andy Lutomirski <luto@amacapital.net> Cc: Dave Hansen <dave.hansen@linux.intel.com> Cc: Fenghua Yu <fenghua.yu@intel.com> Cc: H. Peter Anvin <hpa@zytor.com> Cc: Linus Torvalds <torvalds@linux-foundation.org> Cc: Oleg Nesterov <oleg@redhat.com> Cc: Peter Zijlstra <peterz@infradead.org> Cc: Thomas Gleixner <tglx@linutronix.de> Signed-off-by: Ingo Molnar <mingo@kernel.org>
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@ -20,8 +20,6 @@ struct user_i387_struct;
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extern int fpstate_alloc_init(struct task_struct *curr);
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extern int init_fpu(struct task_struct *child);
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extern void fpu_finit(struct fpu *fpu);
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extern int dump_fpu(struct pt_regs *, struct user_i387_struct *);
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extern void math_state_restore(void);
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@ -283,7 +283,7 @@ EXPORT_SYMBOL_GPL(fpstate_alloc_init);
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* value at reset if we support XMM instructions and then
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* remember the current task has used the FPU.
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*/
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int init_fpu(struct task_struct *tsk)
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static int init_fpu(struct task_struct *tsk)
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{
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int ret;
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@ -306,7 +306,6 @@ int init_fpu(struct task_struct *tsk)
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set_stopped_child_used_math(tsk);
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return 0;
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}
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EXPORT_SYMBOL_GPL(init_fpu);
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/*
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* The xstateregs_active() routine is the same as the fpregs_active() routine,
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