sched/rt: Minimize rq->lock contention in do_sched_rt_period_timer()
With CONFIG_RT_GROUP_SCHED=y, do_sched_rt_period_timer() sequentially takes each CPU's rq->lock. On a large, busy system, the cumulative time it takes to acquire each lock can be excessive, even triggering a watchdog timeout. If rt_rq->rt_time and rt_rq->rt_nr_running are both zero, this function does nothing while holding the lock, so don't bother taking it at all. Signed-off-by: Dave Kleikamp <dave.kleikamp@oracle.com> Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org> Cc: Linus Torvalds <torvalds@linux-foundation.org> Cc: Peter Zijlstra <peterz@infradead.org> Cc: Thomas Gleixner <tglx@linutronix.de> Link: http://lkml.kernel.org/r/a767637b-df85-912f-ba69-c90ee00a3fb6@oracle.com Signed-off-by: Ingo Molnar <mingo@kernel.org>
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@ -840,6 +840,17 @@ static int do_sched_rt_period_timer(struct rt_bandwidth *rt_b, int overrun)
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int enqueue = 0;
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struct rt_rq *rt_rq = sched_rt_period_rt_rq(rt_b, i);
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struct rq *rq = rq_of_rt_rq(rt_rq);
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int skip;
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/*
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* When span == cpu_online_mask, taking each rq->lock
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* can be time-consuming. Try to avoid it when possible.
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*/
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raw_spin_lock(&rt_rq->rt_runtime_lock);
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skip = !rt_rq->rt_time && !rt_rq->rt_nr_running;
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raw_spin_unlock(&rt_rq->rt_runtime_lock);
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if (skip)
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continue;
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raw_spin_lock(&rq->lock);
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if (rt_rq->rt_time) {
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