audit: wait_for_auditd rework for readability
We had some craziness with signed to unsigned long casting which appears wholely unnecessary. Just use signed long. Even though 2 values of the math equation are unsigned longs the result is expected to be a signed long. So why keep casting the result to signed long? Just make it signed long and use it. We also remove the needless "timeout" variable. We already have the stack "sleep_time" variable. Just use that... Signed-off-by: Eric Paris <eparis@redhat.com>
This commit is contained in:
Родитель
8c8115faca
Коммит
c81825dd6b
|
@ -1281,21 +1281,20 @@ static inline void audit_get_stamp(struct audit_context *ctx,
|
|||
/*
|
||||
* Wait for auditd to drain the queue a little
|
||||
*/
|
||||
static unsigned long wait_for_auditd(unsigned long sleep_time)
|
||||
static long wait_for_auditd(long sleep_time)
|
||||
{
|
||||
unsigned long timeout = sleep_time;
|
||||
DECLARE_WAITQUEUE(wait, current);
|
||||
set_current_state(TASK_UNINTERRUPTIBLE);
|
||||
add_wait_queue_exclusive(&audit_backlog_wait, &wait);
|
||||
|
||||
if (audit_backlog_limit &&
|
||||
skb_queue_len(&audit_skb_queue) > audit_backlog_limit)
|
||||
timeout = schedule_timeout(sleep_time);
|
||||
sleep_time = schedule_timeout(sleep_time);
|
||||
|
||||
__set_current_state(TASK_RUNNING);
|
||||
remove_wait_queue(&audit_backlog_wait, &wait);
|
||||
|
||||
return timeout;
|
||||
return sleep_time;
|
||||
}
|
||||
|
||||
/**
|
||||
|
@ -1339,13 +1338,12 @@ struct audit_buffer *audit_log_start(struct audit_context *ctx, gfp_t gfp_mask,
|
|||
while (audit_backlog_limit
|
||||
&& skb_queue_len(&audit_skb_queue) > audit_backlog_limit + reserve) {
|
||||
if (gfp_mask & __GFP_WAIT && audit_backlog_wait_time) {
|
||||
unsigned long sleep_time;
|
||||
long sleep_time;
|
||||
|
||||
sleep_time = timeout_start + audit_backlog_wait_time -
|
||||
jiffies;
|
||||
if ((long)sleep_time > 0) {
|
||||
sleep_time = timeout_start + audit_backlog_wait_time - jiffies;
|
||||
if (sleep_time > 0) {
|
||||
sleep_time = wait_for_auditd(sleep_time);
|
||||
if ((long)sleep_time > 0)
|
||||
if (sleep_time > 0)
|
||||
continue;
|
||||
}
|
||||
}
|
||||
|
|
Загрузка…
Ссылка в новой задаче