PCI: Release OF node in pci_scan_device()'s error path

In pci_scan_device(), if pci_setup_device() fails for any reason, the code
will not release device's of_node by calling pci_release_of_node().  Fix
that by calling the release function.

Fixes: 98d9f30c82 ("pci/of: Match PCI devices to OF nodes dynamically")
Link: https://lore.kernel.org/r/20210124232826.1879-1-dmitry.baryshkov@linaro.org
Signed-off-by: Dmitry Baryshkov <dmitry.baryshkov@linaro.org>
Signed-off-by: Bjorn Helgaas <bhelgaas@google.com>
Reviewed-by: Leon Romanovsky <leonro@nvidia.com>
This commit is contained in:
Dmitry Baryshkov 2021-01-25 02:28:26 +03:00 коммит произвёл Bjorn Helgaas
Родитель a38fd87484
Коммит c99e755a4a
1 изменённых файлов: 1 добавлений и 0 удалений

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@ -2353,6 +2353,7 @@ static struct pci_dev *pci_scan_device(struct pci_bus *bus, int devfn)
pci_set_of_node(dev);
if (pci_setup_device(dev)) {
pci_release_of_node(dev);
pci_bus_put(dev->bus);
kfree(dev);
return NULL;