hexdump: do not print debug dumps for !CONFIG_DEBUG

print_hex_dump_debug() is likely supposed to be analogous to pr_debug() or
dev_dbg() & friends.  Currently it will adhere to dynamic debug, but will
not stub out prints if CONFIG_DEBUG is not set.  Let's make it do the
right thing, because I am tired of having my dmesg buffer full of hex
dumps on production systems.

Signed-off-by: Linus Walleij <linus.walleij@linaro.org>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>

include/linux/printk.h

@@ -456,11 +456,17 @@ static inline void print_hex_dump_bytes(const char *prefix_str, int prefix_type,
 			     groupsize, buf, len, ascii)	\
 	dynamic_hex_dump(prefix_str, prefix_type, rowsize,	\
 			 groupsize, buf, len, ascii)
-#else
+#elif defined(DEBUG)
 #define print_hex_dump_debug(prefix_str, prefix_type, rowsize,		\
 			     groupsize, buf, len, ascii)		\
 	print_hex_dump(KERN_DEBUG, prefix_str, prefix_type, rowsize,	\
 		       groupsize, buf, len, ascii)
-#endif /* defined(CONFIG_DYNAMIC_DEBUG) */
+#else
+static inline void print_hex_dump_debug(const char *prefix_str, int prefix_type,
+					int rowsize, int groupsize,
+					const void *buf, size_t len, bool ascii)
+{
+}
+#endif
 
 #endif