btrfs: factor out reada loop in __reada_start_machine
This is in preparation for moving fs_devices to proper lists. Reviewed-by: Josef Bacik <josef@toxicpanda.com> Reviewed-by: Anand Jain <anand.jain@oracle.com> Signed-off-by: Nikolay Borisov <nborisov@suse.com> Signed-off-by: David Sterba <dsterba@suse.com>
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@ -767,15 +767,13 @@ static void reada_start_machine_worker(struct btrfs_work *work)
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kfree(rmw);
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}
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static void __reada_start_machine(struct btrfs_fs_info *fs_info)
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/* Try to start up to 10k READA requests for a group of devices */
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static int reada_start_for_fsdevs(struct btrfs_fs_devices *fs_devices)
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{
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struct btrfs_device *device;
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struct btrfs_fs_devices *fs_devices = fs_info->fs_devices;
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u64 enqueued;
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u64 total = 0;
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int i;
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struct btrfs_device *device;
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again:
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do {
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enqueued = 0;
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mutex_lock(&fs_devices->device_list_mutex);
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@ -787,6 +785,18 @@ again:
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mutex_unlock(&fs_devices->device_list_mutex);
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total += enqueued;
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} while (enqueued && total < 10000);
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return total;
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}
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static void __reada_start_machine(struct btrfs_fs_info *fs_info)
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{
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struct btrfs_fs_devices *fs_devices = fs_info->fs_devices;
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int i;
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u64 enqueued = 0;
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again:
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enqueued += reada_start_for_fsdevs(fs_devices);
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if (fs_devices->seed) {
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fs_devices = fs_devices->seed;
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goto again;
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