sched/fair: Remove unnecessary comparison with -1

Since commit:

  83a0a96a5f ("sched/fair: Leverage the idle state info when choosing the "idlest" cpu")

find_idlest_group_cpu() (formerly find_idlest_cpu) no longer returns -1,
so we can simplify the checking of the return value in find_idlest_cpu().

Signed-off-by: Brendan Jackman <brendan.jackman@arm.com>
Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Reviewed-by: Josef Bacik <jbacik@fb.com>
Reviewed-by: Vincent Guittot <vincent.guittot@linaro.org>
Cc: Dietmar Eggemann <dietmar.eggemann@arm.com>
Cc: Josef Bacik <josef@toxicpanda.com>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Mike Galbraith <efault@gmx.de>
Cc: Morten Rasmussen <morten.rasmussen@arm.com>
Cc: Peter Zijlstra <peterz@infradead.org>
Cc: Thomas Gleixner <tglx@linutronix.de>
Link: http://lkml.kernel.org/r/20171005114516.18617-3-brendan.jackman@arm.com
Signed-off-by: Ingo Molnar <mingo@kernel.org>

kernel/sched/fair.c

@@ -5933,7 +5933,7 @@ static inline int find_idlest_cpu(struct sched_domain *sd, struct task_struct *p
 		}
 
 		new_cpu = find_idlest_group_cpu(group, p, cpu);
-		if (new_cpu == -1 || new_cpu == cpu) {
+		if (new_cpu == cpu) {
 			/* Now try balancing at a lower domain level of cpu */
 			sd = sd->child;
 			continue;