fib_rules: return 0 directly if an exactly same rule exists when NLM_F_EXCL not supplied
With commit153380ec4b
("fib_rules: Added NLM_F_EXCL support to fib_nl_newrule") we now able to check if a rule already exists. But this only works with iproute2. For other tools like libnl, NetworkManager, it still could add duplicate rules with only NLM_F_CREATE flag, like [localhost ~ ]# ip rule 0: from all lookup local 32766: from all lookup main 32767: from all lookup default 100000: from 192.168.7.5 lookup 5 100000: from 192.168.7.5 lookup 5 As it doesn't make sense to create two duplicate rules, let's just return 0 if the rule exists. Fixes:153380ec4b
("fib_rules: Added NLM_F_EXCL support to fib_nl_newrule") Reported-by: Thomas Haller <thaller@redhat.com> Signed-off-by: Hangbin Liu <liuhangbin@gmail.com> Signed-off-by: David S. Miller <davem@davemloft.net>
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Родитель
80f232121b
Коммит
e9919a24d3
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@ -757,9 +757,9 @@ int fib_nl_newrule(struct sk_buff *skb, struct nlmsghdr *nlh,
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if (err)
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goto errout;
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if ((nlh->nlmsg_flags & NLM_F_EXCL) &&
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rule_exists(ops, frh, tb, rule)) {
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err = -EEXIST;
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if (rule_exists(ops, frh, tb, rule)) {
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if (nlh->nlmsg_flags & NLM_F_EXCL)
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err = -EEXIST;
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goto errout_free;
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}
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