sh: correct definitions to access stack pointers
A definition like: #define regs_return_value(regs) ((regs)->regs[0]) called with regs_return_value(foo) will be preprocessed to: ((foo)->foo[0]) ^^^ So to fix this to ensure the preprocessor compiles such calls correctly. Signed-off-by: Roel Kluin <roel.kluin@gmail.com> Signed-off-by: Paul Mundt <lethal@linux-sh.org>
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@ -40,8 +40,8 @@
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#include <asm/system.h>
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#define user_mode(regs) (((regs)->sr & 0x40000000)==0)
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#define user_stack_pointer(regs) ((unsigned long)(regs)->regs[15])
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#define kernel_stack_pointer(regs) ((unsigned long)(regs)->regs[15])
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#define user_stack_pointer(_regs) ((unsigned long)(_regs)->regs[15])
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#define kernel_stack_pointer(_regs) ((unsigned long)(_regs)->regs[15])
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#define instruction_pointer(regs) ((unsigned long)(regs)->pc)
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extern void show_regs(struct pt_regs *);
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@ -76,7 +76,7 @@ struct pt_dspregs {
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#ifdef __KERNEL__
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#define MAX_REG_OFFSET offsetof(struct pt_regs, tra)
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#define regs_return_value(regs) ((regs)->regs[0])
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#define regs_return_value(_regs) ((_regs)->regs[0])
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#endif /* __KERNEL__ */
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@ -13,7 +13,7 @@ struct pt_regs {
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#ifdef __KERNEL__
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#define MAX_REG_OFFSET offsetof(struct pt_regs, tregs[7])
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#define regs_return_value(regs) ((regs)->regs[3])
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#define regs_return_value(_regs) ((_regs)->regs[3])
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#endif /* __KERNEL__ */
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