Staging: quickstart: free after input_unregister_device()

input_unregister_device() releases "quickstart_input" so the
input_free_device() is a double free.  Also I noticed that there is a
memory leak if the call to input_register_device() fails.

Signed-off-by: Dan Carpenter <error27@gmail.com>
Signed-off-by: Greg Kroah-Hartman <gregkh@suse.de>
This commit is contained in:
Dan Carpenter 2010-11-12 08:04:43 +03:00 коммит произвёл Greg Kroah-Hartman
Родитель 5fb5d38fc2
Коммит ebba26f4a8
1 изменённых файлов: 8 добавлений и 2 удалений

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@ -355,7 +355,6 @@ static int quickstart_acpi_remove(struct acpi_device *device, int type)
static void quickstart_exit(void)
{
input_unregister_device(quickstart_input);
input_free_device(quickstart_input);
device_remove_file(&pf_device->dev, &dev_attr_pressed_button);
device_remove_file(&pf_device->dev, &dev_attr_buttons);
@ -375,6 +374,7 @@ static int __init quickstart_init_input(void)
{
struct quickstart_btn **ptr = &quickstart_data.btn_lst;
int count;
int ret;
quickstart_input = input_allocate_device();
@ -391,7 +391,13 @@ static int __init quickstart_init_input(void)
ptr = &((*ptr)->next);
}
return input_register_device(quickstart_input);
ret = input_register_device(quickstart_input);
if (ret) {
input_free_device(quickstart_input);
return ret;
}
return 0;
}
static int __init quickstart_init(void)