ACPI: PCI: follow typical PCI INTx swizzling pattern

No functional change; this just uses the typical pattern of
PCI INTx swizzling done on other architectures.

Signed-off-by: Bjorn Helgaas <bjorn.helgaas@hp.com>
Signed-off-by: Len Brown <len.brown@intel.com>
This commit is contained in:
Bjorn Helgaas 2008-12-08 21:31:11 -07:00 коммит произвёл Len Brown
Родитель 3b1ea18d3b
Коммит ee40136313
1 изменённых файлов: 7 добавлений и 4 удалений

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@ -399,7 +399,7 @@ static struct acpi_prt_entry *
acpi_pci_irq_derive(struct pci_dev *dev, int pin)
{
struct acpi_prt_entry *entry = NULL;
struct pci_dev *bridge = dev;
struct pci_dev *bridge;
u8 bridge_pin = 0, orig_pin = pin;
@ -407,9 +407,9 @@ acpi_pci_irq_derive(struct pci_dev *dev, int pin)
* Attempt to derive an IRQ for this device from a parent bridge's
* PCI interrupt routing entry (eg. yenta bridge and add-in card bridge).
*/
while (bridge->bus->self) {
pin = (((pin - 1) + PCI_SLOT(bridge->devfn)) % 4) + 1;
bridge = bridge->bus->self;
bridge = dev->bus->self;
while (bridge) {
pin = (((pin - 1) + PCI_SLOT(dev->devfn)) % 4) + 1;
if ((bridge->class >> 8) == PCI_CLASS_BRIDGE_CARDBUS) {
/* PC card has the same IRQ as its cardbridge */
@ -431,6 +431,9 @@ acpi_pci_irq_derive(struct pci_dev *dev, int pin)
pci_name(bridge)));
return entry;
}
dev = bridge;
bridge = dev->bus->self;
}
dev_warn(&dev->dev, "can't derive routing for PCI INT %c\n",