EDAC/pci: Get rid of the silly one-shot memory allocation in edac_pci_alloc_ctl_info()

Use boring kzalloc() instead.

There should be no functional changes resulting from this.

Signed-off-by: Borislav Petkov <bp@suse.de>
Link: https://lore.kernel.org/r/20220310095254.1510-3-bp@alien8.de
This commit is contained in:
Borislav Petkov 2022-03-08 08:37:11 +01:00
Родитель 0bbb265f70
Коммит fb8cd45ca3
1 изменённых файлов: 12 добавлений и 13 удалений

Просмотреть файл

@ -32,29 +32,28 @@ struct edac_pci_ctl_info *edac_pci_alloc_ctl_info(unsigned int sz_pvt,
const char *edac_pci_name)
{
struct edac_pci_ctl_info *pci;
void *p = NULL, *pvt;
unsigned int size;
edac_dbg(1, "\n");
pci = edac_align_ptr(&p, sizeof(*pci), 1);
pvt = edac_align_ptr(&p, 1, sz_pvt);
size = ((unsigned long)pvt) + sz_pvt;
/* Alloc the needed control struct memory */
pci = kzalloc(size, GFP_KERNEL);
if (pci == NULL)
pci = kzalloc(sizeof(struct edac_pci_ctl_info), GFP_KERNEL);
if (!pci)
return NULL;
/* Now much private space */
pvt = sz_pvt ? ((char *)pci) + ((unsigned long)pvt) : NULL;
if (sz_pvt) {
pci->pvt_info = kzalloc(sz_pvt, GFP_KERNEL);
if (!pci->pvt_info)
goto free;
}
pci->pvt_info = pvt;
pci->op_state = OP_ALLOC;
snprintf(pci->name, strlen(edac_pci_name) + 1, "%s", edac_pci_name);
return pci;
free:
kfree(pci);
return NULL;
}
EXPORT_SYMBOL_GPL(edac_pci_alloc_ctl_info);