#include #include #include int task_work_add(struct task_struct *task, struct callback_head *work, bool notify) { struct callback_head *head; /* * Not inserting the new work if the task has already passed * exit_task_work() is the responisbility of callers. */ do { head = ACCESS_ONCE(task->task_works); work->next = head; } while (cmpxchg(&task->task_works, head, work) != head); if (notify) set_notify_resume(task); return 0; } struct callback_head * task_work_cancel(struct task_struct *task, task_work_func_t func) { struct callback_head **pprev = &task->task_works; struct callback_head *work = NULL; unsigned long flags; /* * If cmpxchg() fails we continue without updating pprev. * Either we raced with task_work_add() which added the * new entry before this work, we will find it again. Or * we raced with task_work_run(), *pprev == NULL. */ raw_spin_lock_irqsave(&task->pi_lock, flags); while ((work = ACCESS_ONCE(*pprev))) { read_barrier_depends(); if (work->func != func) pprev = &work->next; else if (cmpxchg(pprev, work, work->next) == work) break; } raw_spin_unlock_irqrestore(&task->pi_lock, flags); return work; } void task_work_run(void) { struct task_struct *task = current; struct callback_head *work, *head, *next; for (;;) { work = xchg(&task->task_works, NULL); if (!work) break; /* * Synchronize with task_work_cancel(). It can't remove * the first entry == work, cmpxchg(task_works) should * fail, but it can play with *work and other entries. */ raw_spin_unlock_wait(&task->pi_lock); smp_mb(); /* Reverse the list to run the works in fifo order */ head = NULL; do { next = work->next; work->next = head; head = work; work = next; } while (work); work = head; do { next = work->next; work->func(work); work = next; cond_resched(); } while (work); } }