There is an assertion in __call_rcu() that checks only the bottom
bit of the rcu_head pointer, rather than the bottom two (as might be
expected for 32-bit systems) or the bottom three (as might be expected
for 64-bit systems). This choice might be a bit surprising in these days
of ubiquitous 32-bit and 64-bit systems. This commit therefore records
the reason for this odd alignment check, namely that m68k guarantees
only two-byte alignment despite being a 32-bit architectures.
Signed-off-by: Paul E. McKenney <paulmck@linux.vnet.ibm.com>
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