227 строки
8.9 KiB
Plaintext
227 строки
8.9 KiB
Plaintext
UNALIGNED MEMORY ACCESSES
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=========================
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Linux runs on a wide variety of architectures which have varying behaviour
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when it comes to memory access. This document presents some details about
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unaligned accesses, why you need to write code that doesn't cause them,
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and how to write such code!
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The definition of an unaligned access
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=====================================
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Unaligned memory accesses occur when you try to read N bytes of data starting
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from an address that is not evenly divisible by N (i.e. addr % N != 0).
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For example, reading 4 bytes of data from address 0x10004 is fine, but
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reading 4 bytes of data from address 0x10005 would be an unaligned memory
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access.
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The above may seem a little vague, as memory access can happen in different
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ways. The context here is at the machine code level: certain instructions read
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or write a number of bytes to or from memory (e.g. movb, movw, movl in x86
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assembly). As will become clear, it is relatively easy to spot C statements
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which will compile to multiple-byte memory access instructions, namely when
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dealing with types such as u16, u32 and u64.
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Natural alignment
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=================
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The rule mentioned above forms what we refer to as natural alignment:
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When accessing N bytes of memory, the base memory address must be evenly
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divisible by N, i.e. addr % N == 0.
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When writing code, assume the target architecture has natural alignment
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requirements.
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In reality, only a few architectures require natural alignment on all sizes
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of memory access. However, we must consider ALL supported architectures;
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writing code that satisfies natural alignment requirements is the easiest way
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to achieve full portability.
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Why unaligned access is bad
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===========================
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The effects of performing an unaligned memory access vary from architecture
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to architecture. It would be easy to write a whole document on the differences
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here; a summary of the common scenarios is presented below:
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- Some architectures are able to perform unaligned memory accesses
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transparently, but there is usually a significant performance cost.
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- Some architectures raise processor exceptions when unaligned accesses
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happen. The exception handler is able to correct the unaligned access,
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at significant cost to performance.
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- Some architectures raise processor exceptions when unaligned accesses
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happen, but the exceptions do not contain enough information for the
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unaligned access to be corrected.
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- Some architectures are not capable of unaligned memory access, but will
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silently perform a different memory access to the one that was requested,
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resulting a a subtle code bug that is hard to detect!
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It should be obvious from the above that if your code causes unaligned
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memory accesses to happen, your code will not work correctly on certain
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platforms and will cause performance problems on others.
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Code that does not cause unaligned access
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=========================================
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At first, the concepts above may seem a little hard to relate to actual
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coding practice. After all, you don't have a great deal of control over
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memory addresses of certain variables, etc.
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Fortunately things are not too complex, as in most cases, the compiler
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ensures that things will work for you. For example, take the following
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structure:
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struct foo {
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u16 field1;
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u32 field2;
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u8 field3;
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};
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Let us assume that an instance of the above structure resides in memory
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starting at address 0x10000. With a basic level of understanding, it would
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not be unreasonable to expect that accessing field2 would cause an unaligned
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access. You'd be expecting field2 to be located at offset 2 bytes into the
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structure, i.e. address 0x10002, but that address is not evenly divisible
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by 4 (remember, we're reading a 4 byte value here).
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Fortunately, the compiler understands the alignment constraints, so in the
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above case it would insert 2 bytes of padding in between field1 and field2.
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Therefore, for standard structure types you can always rely on the compiler
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to pad structures so that accesses to fields are suitably aligned (assuming
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you do not cast the field to a type of different length).
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Similarly, you can also rely on the compiler to align variables and function
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parameters to a naturally aligned scheme, based on the size of the type of
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the variable.
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At this point, it should be clear that accessing a single byte (u8 or char)
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will never cause an unaligned access, because all memory addresses are evenly
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divisible by one.
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On a related topic, with the above considerations in mind you may observe
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that you could reorder the fields in the structure in order to place fields
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where padding would otherwise be inserted, and hence reduce the overall
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resident memory size of structure instances. The optimal layout of the
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above example is:
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struct foo {
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u32 field2;
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u16 field1;
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u8 field3;
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};
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For a natural alignment scheme, the compiler would only have to add a single
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byte of padding at the end of the structure. This padding is added in order
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to satisfy alignment constraints for arrays of these structures.
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Another point worth mentioning is the use of __attribute__((packed)) on a
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structure type. This GCC-specific attribute tells the compiler never to
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insert any padding within structures, useful when you want to use a C struct
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to represent some data that comes in a fixed arrangement 'off the wire'.
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You might be inclined to believe that usage of this attribute can easily
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lead to unaligned accesses when accessing fields that do not satisfy
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architectural alignment requirements. However, again, the compiler is aware
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of the alignment constraints and will generate extra instructions to perform
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the memory access in a way that does not cause unaligned access. Of course,
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the extra instructions obviously cause a loss in performance compared to the
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non-packed case, so the packed attribute should only be used when avoiding
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structure padding is of importance.
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Code that causes unaligned access
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=================================
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With the above in mind, let's move onto a real life example of a function
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that can cause an unaligned memory access. The following function adapted
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from include/linux/etherdevice.h is an optimized routine to compare two
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ethernet MAC addresses for equality.
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unsigned int compare_ether_addr(const u8 *addr1, const u8 *addr2)
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{
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const u16 *a = (const u16 *) addr1;
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const u16 *b = (const u16 *) addr2;
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return ((a[0] ^ b[0]) | (a[1] ^ b[1]) | (a[2] ^ b[2])) != 0;
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}
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In the above function, the reference to a[0] causes 2 bytes (16 bits) to
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be read from memory starting at address addr1. Think about what would happen
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if addr1 was an odd address such as 0x10003. (Hint: it'd be an unaligned
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access.)
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Despite the potential unaligned access problems with the above function, it
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is included in the kernel anyway but is understood to only work on
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16-bit-aligned addresses. It is up to the caller to ensure this alignment or
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not use this function at all. This alignment-unsafe function is still useful
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as it is a decent optimization for the cases when you can ensure alignment,
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which is true almost all of the time in ethernet networking context.
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Here is another example of some code that could cause unaligned accesses:
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void myfunc(u8 *data, u32 value)
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{
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[...]
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*((u32 *) data) = cpu_to_le32(value);
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[...]
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}
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This code will cause unaligned accesses every time the data parameter points
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to an address that is not evenly divisible by 4.
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In summary, the 2 main scenarios where you may run into unaligned access
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problems involve:
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1. Casting variables to types of different lengths
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2. Pointer arithmetic followed by access to at least 2 bytes of data
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Avoiding unaligned accesses
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===========================
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The easiest way to avoid unaligned access is to use the get_unaligned() and
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put_unaligned() macros provided by the <asm/unaligned.h> header file.
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Going back to an earlier example of code that potentially causes unaligned
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access:
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void myfunc(u8 *data, u32 value)
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{
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[...]
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*((u32 *) data) = cpu_to_le32(value);
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[...]
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}
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To avoid the unaligned memory access, you would rewrite it as follows:
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void myfunc(u8 *data, u32 value)
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{
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[...]
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value = cpu_to_le32(value);
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put_unaligned(value, (u32 *) data);
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[...]
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}
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The get_unaligned() macro works similarly. Assuming 'data' is a pointer to
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memory and you wish to avoid unaligned access, its usage is as follows:
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u32 value = get_unaligned((u32 *) data);
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These macros work work for memory accesses of any length (not just 32 bits as
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in the examples above). Be aware that when compared to standard access of
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aligned memory, using these macros to access unaligned memory can be costly in
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terms of performance.
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If use of such macros is not convenient, another option is to use memcpy(),
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where the source or destination (or both) are of type u8* or unsigned char*.
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Due to the byte-wise nature of this operation, unaligned accesses are avoided.
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--
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Author: Daniel Drake <dsd@gentoo.org>
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With help from: Alan Cox, Avuton Olrich, Heikki Orsila, Jan Engelhardt,
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Johannes Berg, Kyle McMartin, Kyle Moffett, Randy Dunlap, Robert Hancock,
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Uli Kunitz, Vadim Lobanov
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