b0380e1350
The fuzzer triggers the below trace.
[ 7763.384369] unchecked MSR access error: WRMSR to 0x689
(tried to write 0x1fffffff8101349e) at rIP: 0xffffffff810704a4
(native_write_msr+0x4/0x20)
[ 7763.397420] Call Trace:
[ 7763.399881] <TASK>
[ 7763.401994] intel_pmu_lbr_restore+0x9a/0x1f0
[ 7763.406363] intel_pmu_lbr_sched_task+0x91/0x1c0
[ 7763.410992] __perf_event_task_sched_in+0x1cd/0x240
On a machine with the LBR format LBR_FORMAT_EIP_FLAGS2, when the TSX is
disabled, a TSX quirk is required to access LBR from registers.
The lbr_from_signext_quirk_needed() is introduced to determine whether
the TSX quirk should be applied. However, the
lbr_from_signext_quirk_needed() is invoked before the
intel_pmu_lbr_init(), which parses the LBR format information. Without
the correct LBR format information, the TSX quirk never be applied.
Move the lbr_from_signext_quirk_needed() into the intel_pmu_lbr_init().
Checking x86_pmu.lbr_has_tsx in the lbr_from_signext_quirk_needed() is
not required anymore.
Both LBR_FORMAT_EIP_FLAGS2 and LBR_FORMAT_INFO have LBR_TSX flag, but
only the LBR_FORMAT_EIP_FLAGS2 requirs the quirk. Update the comments
accordingly.
Fixes:
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.. | ||
Makefile | ||
bts.c | ||
core.c | ||
cstate.c | ||
ds.c | ||
knc.c | ||
lbr.c | ||
p4.c | ||
p6.c | ||
pt.c | ||
pt.h | ||
uncore.c | ||
uncore.h | ||
uncore_discovery.c | ||
uncore_discovery.h | ||
uncore_nhmex.c | ||
uncore_snb.c | ||
uncore_snbep.c |