A Decl->getName() is not unique. However, the debug info descriptors

are uniqued. The debug info descriptor describing record's context is
necessary to keep two Decl's descriptor unique if their name match.

There is more work to do to create descriptors for DeclContext. 
As a temp. step use type's name in FwdDecl.



git-svn-id: https://llvm.org/svn/llvm-project/cfe/trunk@94050 91177308-0d34-0410-b5e6-96231b3b80d8
This commit is contained in:
Devang Patel 2010-01-20 23:56:40 +00:00
Родитель 5bfb8c128c
Коммит d0f251b4cd
1 изменённых файлов: 8 добавлений и 1 удалений

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@ -609,8 +609,15 @@ llvm::DIType CGDebugInfo::CreateType(const RecordType *Ty,
// its members. Finally, we create a descriptor for the complete type (which
// may refer to the forward decl if the struct is recursive) and replace all
// uses of the forward declaration with the final definition.
// A Decl->getName() is not unique. However, the debug info descriptors
// are uniqued. The debug info descriptor describing record's context is
// necessary to keep two Decl's descriptor unique if their name match.
// FIXME : Use RecordDecl's DeclContext's descriptor. As a temp. step
// use type's name in FwdDecl.
std::string STy = QualType(Ty, 0).getAsString();
llvm::DICompositeType FwdDecl =
DebugFactory.CreateCompositeType(Tag, Unit, Decl->getName(),
DebugFactory.CreateCompositeType(Tag, Unit, STy.c_str(),
DefUnit, Line, 0, 0, 0, 0,
llvm::DIType(), llvm::DIArray());