Avoid outputting last progress item twice

A watcher would output the current progress item when it was detached,
in case it missed that item earlier, which would leave the user seeing
some intermediate step of the operation. This commit changes it to only
output it on detach if it didn't already output the same item.

Signed-off-by: Aaron Lehmann <aaron.lehmann@docker.com>
This commit is contained in:
Aaron Lehmann 2015-12-10 16:48:09 -08:00
Родитель ced2d37901
Коммит fde2329eaa
2 изменённых файлов: 10 добавлений и 15 удалений

Просмотреть файл

@ -124,7 +124,6 @@ func (t *transfer) Broadcast(masterProgressChan <-chan progress.Progress) {
default:
}
}
} else {
t.broadcastDone = true
}
@ -159,18 +158,23 @@ func (t *transfer) Watch(progressOutput progress.Output) *Watcher {
defer func() {
close(w.running)
}()
done := false
var (
done bool
lastWritten progress.Progress
hasLastWritten bool
)
for {
t.mu.Lock()
hasLastProgress := t.hasLastProgress
lastProgress := t.lastProgress
t.mu.Unlock()
// This might write the last progress item a
// second time (since channel closure also gets
// us here), but that's fine.
if hasLastProgress {
// Make sure we don't write the last progress item
// twice.
if hasLastProgress && (!done || !hasLastWritten || lastProgress != lastWritten) {
progressOutput.WriteProgress(lastProgress)
lastWritten = lastProgress
hasLastWritten = true
}
if done {

Просмотреть файл

@ -41,15 +41,6 @@ func TestTransfer(t *testing.T) {
if p.Current != 0 {
t.Fatalf("got unexpected progress value: %d (expected 0)", p.Current)
}
} else if p.Current == 10 {
// Special case: last progress output may be
// repeated because the transfer finishing
// causes the latest progress output to be
// written to the channel (in case the watcher
// missed it).
if p.Current != 9 && p.Current != 10 {
t.Fatalf("got unexpected progress value: %d (expected %d)", p.Current, val+1)
}
} else if p.Current != val+1 {
t.Fatalf("got unexpected progress value: %d (expected %d)", p.Current, val+1)
}