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read-cache: speed up has_dir_name (part 1)
Teach has_dir_name() to see if the path of the new item is greater than the last path in the index array before attempting to search for it. has_dir_name() is looking for file/directory collisions in the index and has to consider each sub-directory prefix in turn. This can cause multiple binary searches for each path. During operations like checkout, merge_working_tree() populates the new index in sorted order, so we expect to be able to append in many cases. This commit is part 1 of 2. This commit handles the top of has_dir_name() and the trivial optimization. Signed-off-by: Jeff Hostetler <jeffhost@microsoft.com> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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e5494631ed
Коммит
06b6d81b79
45
read-cache.c
45
read-cache.c
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@ -910,6 +910,9 @@ int strcmp_offset(const char *s1, const char *s2, size_t *first_change)
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/*
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* Do we have another file with a pathname that is a proper
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* subset of the name we're trying to add?
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*
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* That is, is there another file in the index with a path
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* that matches a sub-directory in the given entry?
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*/
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static int has_dir_name(struct index_state *istate,
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const struct cache_entry *ce, int pos, int ok_to_replace)
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@ -918,6 +921,48 @@ static int has_dir_name(struct index_state *istate,
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int stage = ce_stage(ce);
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const char *name = ce->name;
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const char *slash = name + ce_namelen(ce);
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size_t len_eq_last;
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int cmp_last = 0;
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/*
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* We are frequently called during an iteration on a sorted
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* list of pathnames and while building a new index. Therefore,
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* there is a high probability that this entry will eventually
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* be appended to the index, rather than inserted in the middle.
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* If we can confirm that, we can avoid binary searches on the
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* components of the pathname.
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*
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* Compare the entry's full path with the last path in the index.
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*/
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if (istate->cache_nr > 0) {
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cmp_last = strcmp_offset(name,
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istate->cache[istate->cache_nr - 1]->name,
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&len_eq_last);
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if (cmp_last > 0) {
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if (len_eq_last == 0) {
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/*
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* The entry sorts AFTER the last one in the
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* index and their paths have no common prefix,
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* so there cannot be a F/D conflict.
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*/
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return retval;
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} else {
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/*
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* The entry sorts AFTER the last one in the
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* index, but has a common prefix. Fall through
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* to the loop below to disect the entry's path
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* and see where the difference is.
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*/
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}
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} else if (cmp_last == 0) {
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/*
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* The entry exactly matches the last one in the
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* index, but because of multiple stage and CE_REMOVE
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* items, we fall through and let the regular search
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* code handle it.
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*/
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}
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}
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for (;;) {
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int len;
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