diff --stat: ensure at least one '-' for deletions, and one '+' for additions

The number of '-' and '+' is still linear. The idea is that
scaled-length := floor(a * length + b) with the following constraints: if
length == 1, scaled-length == 1, and the combined length of plusses
and minusses should not be larger than the width by a small margin. Thus,

	a + b == 1

and
	a * max_plusses + b + a * max_minusses + b = width + 1

The solution is

	a * x + b = ((width - 1) * (x - 1) + max_change - 1)
		 / (max_change - 1)

Signed-off-by: Johannes Schindelin <Johannes.Schindelin@gmx.de>
Signed-off-by: Junio C Hamano <junkio@cox.net>
This commit is contained in:
Johannes Schindelin 2006-09-28 17:37:39 +02:00 коммит произвёл Junio C Hamano
Родитель 5c5b2ea9ab
Коммит 3ed74e608a
1 изменённых файлов: 7 добавлений и 4 удалений

11
diff.c
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@ -550,9 +550,12 @@ const char mime_boundary_leader[] = "------------";
static int scale_linear(int it, int width, int max_change)
{
/*
* round(width * it / max_change);
* make sure that at least one '-' is printed if there were deletions,
* and likewise for '+'.
*/
return (it * width * 2 + max_change) / (max_change * 2);
if (max_change < 2)
return it;
return ((it - 1) * (width - 1) + max_change - 1) / (max_change - 1);
}
static void show_name(const char *prefix, const char *name, int len,
@ -684,9 +687,9 @@ static void show_stats(struct diffstat_t* data, struct diff_options *options)
dels += del;
if (width <= max_change) {
total = scale_linear(total, width, max_change);
add = scale_linear(add, width, max_change);
del = total - add;
del = scale_linear(del, width, max_change);
total = add + del;
}
show_name(prefix, name, len, reset, set);
printf("%5d ", added + deleted);