fast-import: use pointer-to-pointer to keep list tail

This is shorter, idiomatic, and it means the compiler does
not get confused about whether our "e" pointer is valid,
letting us drop the "e = e" hack.

Signed-off-by: Jeff King <peff@peff.net>
Reviewed-by: Jonathan Nieder <jrnieder@gmail.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Jeff King 2013-03-21 07:08:17 -04:00 коммит произвёл Junio C Hamano
Родитель 1c71541ddd
Коммит 4db34cc134
1 изменённых файлов: 4 добавлений и 6 удалений

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@ -2613,7 +2613,7 @@ static int parse_from(struct branch *b)
static struct hash_list *parse_merge(unsigned int *count)
{
struct hash_list *list = NULL, *n, *e = e;
struct hash_list *list = NULL, **tail = &list, *n;
const char *from;
struct branch *s;
@ -2641,11 +2641,9 @@ static struct hash_list *parse_merge(unsigned int *count)
die("Invalid ref name or SHA1 expression: %s", from);
n->next = NULL;
if (list)
e->next = n;
else
list = n;
e = n;
*tail = n;
tail = &n->next;
(*count)++;
read_next_command();
}